3[a+1]-5=3a-2

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Solution for 3[a+1]-5=3a-2 equation: 


Simplifying
3[a + 1] + -5 = 3a + -2

Reorder the terms:
3[1 + a] + -5 = 3a + -2
[1 * 3 + a * 3] + -5 = 3a + -2
[3 + 3a] + -5 = 3a + -2

Reorder the terms:
3 + -5 + 3a = 3a + -2

Combine like terms: 3 + -5 = -2
-2 + 3a = 3a + -2

Reorder the terms:
-2 + 3a = -2 + 3a

Add '2' to each side of the equation.
-2 + 2 + 3a = -2 + 2 + 3a

Combine like terms: -2 + 2 = 0
0 + 3a = -2 + 2 + 3a
3a = -2 + 2 + 3a

Combine like terms: -2 + 2 = 0
3a = 0 + 3a
3a = 3a

Add '-3a' to each side of the equation.
3a + -3a = 3a + -3a

Combine like terms: 3a + -3a = 0
0 = 3a + -3a

Combine like terms: 3a + -3a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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